//  Two Sets

#include<bits/stdc++.h>

using namespace std;
using ll = long long;

int main() {
    ll n; cin >> n;
    if ((n * (n+1) / 2) & 1) {
        cout << "NO" << endl;
        return 0;
    }
    cout << "YES" << endl;
    ll target_sum = n * (n+1) / 4;
    vector<ll> first;
    vector<ll> second;
    for (ll i = n; i > 0; i--) {
        if (i <= target_sum) {first.push_back(i); target_sum -= i;}
        else second.push_back(i);
    }
    cout << first.size() << endl;
    for (auto e : first) cout << e << " ";
    cout << '\n' << second.size() << '\n';
    for (auto e: second) cout << e << " ";
    cout << endl;
    return 0;
}